JimmyDouglas Posted May 8, 2016 Share Posted May 8, 2016 Really embarrassing question from a "silly old codger"...How do I remove the road-wheels from an 11-plate Fiesta Titanium?, the wheels are the original 15-spoke alloys. I have the key for the lock-nut but the others have some kind of (tin-plate/alloy) covers. I've "You-Tubed" it "Drill & pick"??? I can't believe THAT!, searched this forum,...even checked the Owner's Manual,...no mention!!! Apologies in advance!!! Quote Link to comment Share on other sites More sharing options...
iantt Posted May 8, 2016 Share Posted May 8, 2016 the tin-plate/alloy covers as you desvribe it is part of the wheel nut assy, just put your wheel wrench on and undo. 2 Quote Link to comment Share on other sites More sharing options...
turbohater Posted May 8, 2016 Share Posted May 8, 2016 Yet another stupid,money maker from Ford.Make sure the socket is the correct metric size,not an A/F equivelent one and that it goes all the way on.If the nut is really tight the sides round quite easily if not done correct as i found out, 1 Quote Link to comment Share on other sites More sharing options...
Mordey Posted May 8, 2016 Share Posted May 8, 2016 The tin-plate/alloy covers eventually fall off. You then have to find another size socket to fit. I had to go up the scrappy for 4 new ones because once missing they look sxxx. 1 Quote Link to comment Share on other sites More sharing options...
JimmyDouglas Posted May 8, 2016 Author Share Posted May 8, 2016 Thank you iantt, turbohater, and Mordey...I thought I was just being "thick"...My very Best Regards. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Ford UK Shop
Sponsored Ad
Name: eBay
Ford Model: FordUK Shop
Ford Year: 2024
Latest Deals
Ford UK Shop for genuine Ford parts & accessoriesDisclaimer: As the club is an eBay Partner, The club may be compensated if you make a purchase via the club
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.